![]() ![]() Now play as Harp Player and score more than 150 points to add Drummer to the roster. ![]() This is a chain of interconnected players. Now when you have obtained Bagpipe Player, play as one and score 150 points to get this Disney Crossy Road secret character. Use Horn Player and score more than 150 points in a single run to get the Bagpipe Player. Unlock the Horn Player to get this character. But don’t worry as you can do this through multiple runs. This might sound difficult to achieve in a single run. Play as Hookhand in the Tangled mode and play the piano 10 times. While playing as Mufasa, get stamped by a herd of wildebeest. To get Scar, you will have to unlock Mufasa first. While on your run, get struck by lightning twice to unlock this secret character. With the help of items won or purchased in the game store, the player can personalize his character.You can play as any Jungle Book character to get Adult Nala.Level collection – read the characters – regularly updated with new challenges.The game also contains links to social networks and third-party advertising.The game contains in-app purchases for real money.Each level should be completed in the least amount of time and steps. ![]() Each level of the game is one upset from the Disney Universe. More than three dishes in a row reward the player with bonuses and the ability to unlock new characters, and for characters – to unlock new abilities.Three dishes stacked in a row disappear from the playing field to move to the table of the guests of the Disney restaurant.The player combines three or more confections into one horizontal or vertical row.The challenges are to help Disney characters Mickey, Minnie, Buzzo, Belle, Alice, Lightyear, Jack Skellington and others serve complex breakfasts, lunches and dinners of three sweet courses on the restaurant table. The player will have to go through 480 tests filled with sweets and the magic of fairy tales. Magical Sweets is an educational match-3 game about cooking – dishes served in Disneyland restaurants. ![]()
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